Proving Z is a Ring with Addition and Subtraction

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Homework Statement


Prove that Z with the following addition and subtraction is a ring.



Homework Equations


a\oplusb = a + b - 1 and a\odotb = ab - (a + b) + 2



The Attempt at a Solution

I proved all the axioms for addition. I'm stuck on the multiplication part.

(a\odotb)\odotc = (ab-(a+b)+2)c - (ab-(a+b)+2+c) + 2

a\odot(b\odotc) = a(bc-(b+c)+2) - (a+bc-(b+c)+2) + 2

How are these equal? I know it's a ring because a couple problems later, my books wants me to prove that it's an integral domain...
 
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I think they are equal. Just expand them out.
 
(ab-(a+b)+2)c - (ab-(a+b)+2+c) + 2 =

abc-ac-bc+2c-ab+a+b-2-c+2 = abc-ac-bc-ab+c+a+b

a(bc-(b+c)+2) - (a+bc-(b+c)+2) + 2 =

abc-ab-ac+2a-a-bc+b+c-2+2 = abc-ab-ac-bc+a+b+c

It looks so much clearer now. My own handwriting was deceiving me... Gah, that's the second stupid question I've posted this weekend...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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