Pulley question about a mass on a string

AI Thread Summary
The discussion revolves around a physics problem involving a pulley and a mass on a string. The user is struggling to calculate the tension in the rope, initially arriving at 2.5 N, while the correct answer is 2.4 N. The confusion stems from misunderstanding the relationship between the forces acting on the mass, particularly the weight and tension. It is clarified that the net force equation should be applied, where the weight of the object minus the tension equals the mass times acceleration. The importance of correctly identifying the forces and their directions is emphasized for solving the problem accurately.
slain4ever
Messages
63
Reaction score
0

Homework Statement



i'm having a lot of trouble with this question.


A pulley, consisting of a 0.40 m diameter wheel mounted on a horizontal frictionless axle, is firmly attached to the ceiling. A light rope wrapped around the pulley supports a 0.50 kg object, as shown in the diagram below. Any motion of the rope causes the pulley to turn, with no slipping between the rope and pulley. When released from rest, the object accelerates downward at 5.0 m/s2.

1) find the tension in the rope.
2) the torque on the pulley from the rope
3) the angular acceleration of the pulley
4) the moment of inertia of the pulley.


Homework Equations



F=T+ma = 0

The Attempt at a Solution



I'm stuck on the first part i keep getting 2.5N since the tension = ma it should be T=5m/s^2 * 0.5 kg but the answers say 2.4N and I can't figure out why. I am assuming it has something to do with the pulley but since it is frictionless i don't see how it adds tension.
 
Physics news on Phys.org
slain4ever said:
Relevant equations

F=T+ma = 0

The Attempt at a Solution



I'm stuck on the first part i keep getting 2.5N since the tension = ma it should be T=5m/s^2 * 0.5 kg but the answers say 2.4N and I can't figure out why. I am assuming it has something to do with the pulley but since it is frictionless i don't see how it adds tension.
Look at your relevant equation again,T does not = ma. Use your relevant equation by first identifying the value of F acting on the object.
 
f= ma
0.5 kg * 5 m/s^2
=2.5 N
 
looking at the forces acting on the object, its weight acts down and the tension acts up. Since the object is falling and accelerating down, the weight force must be greater than the tension force, thus, from Newton 2,
F_net = ma
mg -T =ma
Solve for T.
Note that tension forces always pull away from the objects on which they act, and that acceleration is always in the direction of the net force.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Replies
3
Views
2K
Replies
12
Views
1K
Replies
23
Views
3K
Replies
15
Views
6K
Replies
29
Views
5K
Replies
8
Views
4K
Replies
30
Views
3K
Back
Top