Pulse of neutrinos, E m, hits plasma->charge seperation?

  • Thread starter Thread starter Spinnor
  • Start date Start date
  • Tags Tags
    Neutrinos Pulse
Spinnor
Gold Member
Messages
2,227
Reaction score
419
Pulse of neutrinos, E>>m, hits plasma-->charge seperation?

When a large pulse of neutrinos, each with an energy much greater than the electron rest mass energy, hits some plasma does this give rise to charge separation for the plasma? Could one make a simple argument why this is true or false?

Thanks for any help.
 
Physics news on Phys.org


The answer seems to be "yes", but a simple argument? I found a couple of papers that use a fluid approach, but this is beyond my pay grade. http://www.springerlink.com/content/y721025uj77krm77/

http://pop.aip.org/phpaen/v11/i4/p1352_s1?isAuthorized=no
aip said:
Using dynamical techniques of the plasma physics, the neutrino (antineutrino) effective charge in a magnetized dense electron–positron plasma is determined here. It shown that its value, which is determined by the plasma collective processes, depends mainly on the propagation direction of plasma waves and neutrinos against the external magnetic field direction. The direction dependence of the effective charge occurs due to the fact that the magnetic field breaks the plasma isotropy. The present theory gives a unified picture of the problem which is valid for an external magnetic field below the Landau–Schwinger critical value. Comparison with some of the results from the quantum field theory has been made. © 2004 American Institute of Physics.

Here is the separation of the neutrino fluid in an early universe model: http://arxiv.org/PS_cache/astro-ph/pdf/0211/0211087v2.pdf
 
Last edited by a moderator:
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top