- #1
spiky
- 9
- 0
Hello,
suppose we have a sinusoidal AC source connected to only a pure inductor of self inductance L ( no resistance at all ) ..then emf induced in the inductor is L * dI/dt and is equal and opposite to the applied emf. but if the induced emf opposes the applied emf , then how can there be a current at all in the circuit and in the inductor ?
Thanks.
suppose we have a sinusoidal AC source connected to only a pure inductor of self inductance L ( no resistance at all ) ..then emf induced in the inductor is L * dI/dt and is equal and opposite to the applied emf. but if the induced emf opposes the applied emf , then how can there be a current at all in the circuit and in the inductor ?
Thanks.