- #1
paigegail
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We were given the answer to this puzzler and its 71.96875 N
You calculated the time to fall correctly. But you are using the wrong horizontal distance to calculate the horizontal speed of the box as it falls:Originally posted by paigegail
Consider horizontal
¥Äx = 7.5 + 5= 12.5 m
Relax...Originally posted by paigegail
Ok...so I have that. But what is SOOOOO EXTREMELY FRUSTRATING...IS WHAT DO I DO AFTER I HAVE ALL THAT! The acceleration becomes 0.4163 m/s-squared-. F= ma... that makes is 10.8(0.4163)=4.49604 N that's no where near the answer.
How did you calculate the acceleration?Originally posted by paigegail
K...I found acceleration wrong. I realized that.
Acceleration = 1.733 m/s -squared-
Originally posted by paigegail
Acceleration = 1.733 m/s -squared-
You have a typo: the value for v is not 4.16, it's 4.61.Originally posted by paigegail
v-squared- = vo-squared- + 2aDelta X
4.163 -squared- = 0 + 2(5)a
17.330569 =10a
a=1.733
The horizontal speed of a falling box can be calculated by using the formula v = d/t, where v is the velocity, d is the horizontal distance traveled, and t is the time the box takes to fall.
The horizontal speed of the falling box should be expressed in meters per second (m/s).
Yes, the horizontal speed of the box is affected by air resistance. As the box falls, it will experience air resistance which will slow down its horizontal speed.
No, the horizontal speed of the box cannot be greater than its vertical speed. In a free fall, the vertical and horizontal speeds are directly proportional, so if the box has a greater vertical speed, its horizontal speed will also be greater.
The horizontal speed of the box, along with the vertical speed, can be used to predict the landing location of the box. By knowing the initial horizontal speed and the time it takes to fall, you can calculate the horizontal distance traveled and determine where the box will land.