- #1
kidsasd987
- 143
- 4
http://quantumfreak.com/derivation-of-pvnrt-the-equation-of-ideal-gas/
here is the link.
so we assume the particle hits two surfaces of the cube, thus pressure is 1/3.
combine the equation #11 and #12 we solve kinetic energy equation #12 for mv2.
13. mv^2=2E_{kinetic}\Rightarrow\frac{mv^2}{3}=\frac{2E_{kinetic}}{3}
My question is, I don't understand where 1/3 comes from. is this because the pressure is 1/3?
Thanks for all your help:)
here is the link.
so we assume the particle hits two surfaces of the cube, thus pressure is 1/3.
combine the equation #11 and #12 we solve kinetic energy equation #12 for mv2.
13. mv^2=2E_{kinetic}\Rightarrow\frac{mv^2}{3}=\frac{2E_{kinetic}}{3}
My question is, I don't understand where 1/3 comes from. is this because the pressure is 1/3?
Thanks for all your help:)