QM: psi(x,t) for Gaussian Wave Packet

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SUMMARY

The discussion focuses on finding the time-dependent wave function psi(x,t) for a Gaussian wave packet, specifically starting from the initial condition psi(x,0) = Aexp(-ax^2). The user successfully normalized the wave function, determining A = (pi/a)^-1/4, and derived the expression for psi(k). The conversation highlights the importance of completing the square in the integration process and the application of the exponential property e^(A+B) = e^A * e^B to simplify the integral, ultimately leading to the solvable integral of exp(-y^2).

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  • Understanding of quantum mechanics, specifically wave functions and their evolution.
  • Familiarity with Fourier transforms, particularly the equations phi(k) and psi(x,t).
  • Knowledge of integration techniques, including integration by parts and completing the square.
  • Proficiency in handling Gaussian integrals and their properties.
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  • Study the derivation of the Fourier transform and its applications in quantum mechanics.
  • Learn about Gaussian wave packets and their significance in quantum mechanics.
  • Explore advanced integration techniques, focusing on completing the square and Gaussian integrals.
  • Investigate the properties of exponential functions in the context of quantum mechanics.
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Students and professionals in quantum mechanics, physicists working with wave functions, and anyone interested in the mathematical techniques used to solve quantum problems involving Gaussian wave packets.

Gumbercules
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Homework Statement


For a free particle, Given psi(x,0) = Aexp(-ax^2), find psi(x,t)


Homework Equations


phi(k) = 1/(sqrt(2pi)) times integral from -inf to +inf (psi(x,0)exp(-ikx))dx
psi(x,t) = 1/(sqrt(2pi)) times integral from -inf to +inf (phi(k)exp(i(kx - (hk^2)t/2m)))dk
my apologies for the messy notation


The Attempt at a Solution


I have normalized psi(x,0) to get A = (pi/a)^-1/4 and have my psi(k) = (1/(sqrt(2pi))) ((pi/a)^-1/4) times integral from -inf to +inf (exp(-ax^2) exp(-ikx)) dx.

regrettably, my math is quite out of practice, and I am unsure how to proceed. the text says something about 'completing the square' which gives y = (sqrt(a))[x + (b/2a)], then ((ax^2) + bx) = (y^2) - (b^2)/4a. After this, integration by parts doesn't seem to help (or I'm missing something, which is quite likely). Any help is greatly appreciated!
 
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Why do you need integration by parts? Maybe you've just been staring at QM too long. If A and B are c-numbers, then eAB=eAeB. One of these factors will come out of the integral.
 
Perhaps you are right Turin, I do feel a little braindead at the moment. Do you mean exp(a+b) = exp(a)exp(b)? In that case, I would take the exp((b^2)/4a) out of the integral, which would leave the integral from -inf to + inf (exp(-y^2)), which I can solve. My apologies if I have this wrong, maybe I should come back to it later.
 

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