Calculating Magnetic Flux Density in a Solenoid

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The magnetic flux density B inside a solenoid is calculated using the formula B = permeability of free space x n x I, where n represents the number of turns per meter. For a solenoid with n = 100 turns/m and I = 2 Amperes, B can be calculated for any length of the solenoid. In a 10 cm length of the same solenoid, the formula remains the same, as the magnetic field strength is uniform along the length of the solenoid. The length of the solenoid does not affect the magnitude of the B-field, as it is determined by the current and the number of turns per unit length. Understanding these principles is crucial for accurate calculations in electromagnetism.
ryan9907
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The magnetic flux density B( in tesla ) inside the solenoid and parallel to its axis is given by the expression

B= permeability of free space x n x I, where n is the number of turns per metre length of the solenoid

my question is so for example, if n = 100turns in 1m and I = 2Ampere


in 1m length of solenoid B= permeability of free space x 100 x 2A

how about the B-field in like 10cm of the same solenoid?

i still use the same formula B= permeability of free space x 100 x 2A? or use 10 instead of 100?

2. does the length of solenoid affect the magnitude of B-field in the coil??

thanks for the help
 
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