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**[SOLVED] Quadratic Equations and Inequalities question about properties of quadratic**

so here is the question

graph the function. state the domain and range of the function.

F(x)=-2x^2-3x+2

i try and use the axis of symmetry (-b/2a) and then plug that into the original formula to get the vertex.

i keep getting F(-3/2)=2

but then when i try and plug in numbers into the formula there scattered everywhere

F(-3/2)=2 is the vertex in the graph but i cant find the other points to show where the parabola is going

i tried -1/2, 0, -2 and got

(-1/2,3)

(0,-3)

(-2,0)

please help me out.

its supposed to be a upside down parabola with a domain of all real number and a range of {y|y<_ 25/8}

<_ = less than or equal to.

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