Quantum interference with different polarization

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In the discussion on quantum interference with different polarization angles in a double slit experiment, two conflicting views are presented. One source, Wikipedia, asserts that interference fringes require waves to have the same polarization, as differing polarizations cannot effectively combine. Conversely, another response suggests that interference does occur with different polarization angles, with intensity described by the formula I=I_1+I_2+2√(I_1I_2)cos(α), indicating a gradual transition to no interference as angles diverge. The debate centers on whether interference can happen with non-parallel polarizations, highlighting the complexity of wave interactions in quantum mechanics. Further references, such as an arXiv paper, suggest that only aligned components contribute to interference.
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Hi all,

Imagine a double slit experiment where each slit contains a polarization filter with some angle relative to each other (\alpha). If the polarization filters are parallel the usual interference pattern will emerge, and when they are perpendicular no interference pattern will emerge. What happens when they have different relative angles, though?
The problem is that I've read two different sources, Wikipedia states:
The two waves must have the same polarization to give rise to interference fringes since it is not possible for waves of different polarizations to cancel one another out or add together. Instead, when waves of different polarization are added together, they give rise to a wave of a different polarization state.

While someone answered a question saying that it did interfere and that the intensity would be:
I=I_1+I_2+2\sqrt{I_1I_2}cos(\alpha)

It claims that there are still the same interference pattern, but it simply gets closer to no interference.

So which is right?Thanks in advance
 
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Do you have a reference for the second answer?
Also see: http://arxiv.org/pdf/1110.4309.pdf
p8 ... the argument is that the components that are aligned in polarity interfere.
 
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