- #1
iScience
- 466
- 5
i'm trying to do the following integral:
$$\int{e^{\frac{-2amx^2}{ħ}}dx}$$ (in case this is hard to see, the exponent is $$\frac{-2amx^2}{ħ}$$)
where a, m are real constants
but inside the integral can't i split this up into two exponentials?
$$\int{e^{\frac{-2am}{ħ}}e^{x^2}dx} = e^{\frac{-2am}{ħ}}\int{e^{x^2}dx}$$
if not, then why not?..
$$\int{e^{\frac{-2amx^2}{ħ}}dx}$$ (in case this is hard to see, the exponent is $$\frac{-2amx^2}{ħ}$$)
where a, m are real constants
but inside the integral can't i split this up into two exponentials?
$$\int{e^{\frac{-2am}{ħ}}e^{x^2}dx} = e^{\frac{-2am}{ħ}}\int{e^{x^2}dx}$$
if not, then why not?..