Quantum Mechanics: Substitution and Coulomb Potential in Schrodinger Equation

[spaghetti3451]

Homework Statement

(i) Briefly indicate how substitution of operators corresponding to dynamical variables in an eigenvalue equation leads to the Schrodinger equation \left( \frac{-ħ^{2}}{2m} ∇^{2} + V \right)ψ = Eψ.

(ii) What is the Coulomb potential, V(r), of an electron, charge e, in a hydrogen atom at distance r from the nucleus?

(iii), (iv), (v) left out for the moment

Homework Equations

The Attempt at a Solution

(i) (T + V) = E : law of conservation of energy

Multiply by ψ to obtain an eigenvalue equation: (T + V)ψ = Eψ

Substitute operators \widehat{T} and \widehat{V} corresponding to the dynamical variables T and V in the eigenvalue equation: ( \widehat{T} + \widehat{V} ) ψ = Eψ

\widehat{T} = \frac{\widehat{p}^{2}}{2m} = \frac{(-iħ∇)^{2}}{2m} = \frac{-ħ^{2}}{2m} ∇^{2}

\widehat{V} = V

So, the eigenvalue equation becomes the Schrodinger equation \left( \frac{-ħ^{2}}{2m} ∇^{2} + V \right)ψ = Eψ.(ii) V(r) = \frac{-e^{2}}{4πε₀r}

Any comments would be greatly appreciated.

 

[BruceW]

yep, your answers look good to me.