Quantum Mechanics - Superposition of Wavefunctions?

Click For Summary
SUMMARY

The discussion centers on the concept of superposition in quantum mechanics, specifically regarding the wavefunctions ψ1, ψ2, and their linear combination ψ3. Participants clarify that while ψ3 is derived from ψ1 and ψ2, the probabilities associated with these states do not simply add up; thus, p3 does not equal p1 + p2. The linearity of wavefunctions allows for superposition, but it creates a distinct state that alters probability distributions. This leads to the conclusion that superposition results in a new probability distribution rather than a straightforward summation of individual probabilities.

PREREQUISITES
  • Understanding of wavefunctions in quantum mechanics
  • Familiarity with the Schrödinger equation
  • Knowledge of linear algebra concepts as they apply to quantum states
  • Basic principles of probability in quantum mechanics
NEXT STEPS
  • Study the principles of quantum superposition in detail
  • Explore the implications of the linearity of wavefunctions
  • Learn about probability distributions in quantum mechanics
  • Investigate specific examples of superposition and their outcomes in quantum systems
USEFUL FOR

Students and educators in quantum mechanics, physicists exploring wavefunction behavior, and anyone interested in the foundational principles of quantum theory.

pearapple
Messages
10
Reaction score
0

Homework Statement


The wavefunction for a particle in one dimension is given by
ψ1. Another state the particle may be in is ψ2. A third state the particle could be in is ψ3.

Looking at the wavefunctions, ψ3 is ψ1 and ψ2 added together.

Is the probability of being in a given interval in ψ3 the same as the separate probabilities for ψ1 and ψ2 for that interval?

Homework Equations





The Attempt at a Solution


I don't really understand how superposition works. I read something about the ψ's being linear, so a linear combination of ψ1 and ψ2 (ie. ψ3) is still a solution to the Schrödinger equation.

Is the superposition state a completely different state still though? I don't get why I am being asked this question. If it's a mixture of the two states, the probabilities would change wouldn't they? I don't see the link here.
 
Physics news on Phys.org
Suppose the particle is in the state ψ1 and say the probability of finding it in the interval a ≤ x ≤ b is p1. Similarly, suppose the particle is in the state ψ2 and the corresponding probability is p2, and likewise for state ψ3.

The question is asking you, I believe, if it's true that p3 = p1 + p2.
 
Thanks! I believe you're right.

In general, I don't think p3 = p1 + P2.

I don't think I could explain why though. I just don't see WHY those would be equal, because although state 3 is a superposition, it is still a new state is it not? Is there some situation in which p3 = p1 + P2 is true?
 

Similar threads

Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
969
Replies
1
Views
6K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K