Quantum mechanics wave function

AI Thread Summary
To calculate the probability density |\Psi(x,t)|^{2} for the given quantum mechanics wave function, one must multiply the wave function by its complex conjugate. This process eliminates the imaginary components, resulting in a real-valued expression. The discussion emphasizes that the presence of 'i' in the equation should vanish after simplification. Participants encourage sharing calculations for assistance in identifying errors or further simplification. The conversation highlights the importance of understanding complex numbers in quantum mechanics.
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Homework Statement


One of the quantum mechanics wave functions of a particle of unit mass trapped in an infinite potential square well of width 1 unit is given by

Ψ(x,t)= sin(\pix)e^{-i(\pi^2\overline{h}/2)t} + sin(2\pix)e^{-i(4\pi^2\overline{h}/2)t}\

where \overline{h} is a certain constant. Calculate |\Psi(x,t)|^{2}

Homework Equations





The Attempt at a Solution


I know to calculate |\Psi(x,t)|^{2} I need to separate the real and imaginary parts, but I'm not sure how to get started.
 
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Use eiz = cos(z) + i·sin(z)

Alternatively, you could multiply ψ by its complex conjugate.
 
If I multiply by the complex conjugate, I'll get |\Psi(x,t)|^{2}?
 
I multiplied it by the complex conjugate, but there are still i's in the equation. Aren't there supposed to be no i's?
 
That's right. If you multiply by the conjugate and simplify, there should be no i's left.

Show us your calculations.
 
Sorry about not responding sooner. Somehow I missed seeing this thread's new activity in my subscribed threads lists, until just now.

gotmilk04 said:
If I multiply by the complex conjugate, I'll get |\Psi(x,t)|^{2}?
Yes. This is true of any complex number.

Let z = x + iy, where x and y are real.

Then

z·z* = (x + iy)·(x - iy) = [algebra left as an exercise to the reader] = |z|2

If you post your calculation, we can help either spotting an error or with how to simplify your expression further.
 
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