Quantum physics potential well.

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SUMMARY

The discussion focuses on calculating the momentum space wave function for a particle in an infinite potential well, defined by the wave function \(\psi(x) = \sqrt{\frac{2}{a}}\text{Sin}\left[\frac{n*\text{Pi}*x}{a}\right]\). The correct approach involves using the Fourier transform, represented by the equation \(\phi(p) = \sqrt{\frac{1}{2*\text{Pi}*\hbar}}\int_0^a e^{-i*p*x/\hbar}dx \sqrt{\frac{2}{a}}\text{Sin}\left[\frac{n*\text{Pi}*x}{a}\right]\). The potential well is characterized by zero potential between the boundaries 0 and a, confirming the application of the Fourier transform in this context.

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  • Understanding of quantum mechanics principles, specifically wave functions.
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  • Knowledge of potential wells, particularly infinite potential wells.
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arierreF
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Homework Statement



In the instant t=0, we have the following wave function of a particle in a infinite potential well with a width [itex]a[/itex].

[itex]\psi (x) = \sqrt{\frac{2}{a}}\text{Sin}\left[\frac{n*\text{Pi}*x}{a}\right][/itex]


Calculate the momentum space wave function.



Ok, i just want to confirm if i have to use the following equation to calculate momentum space wave function:

[itex]\phi (p) = \sqrt{\frac{1}{2*\text{Pi}*\hbar}}\int _0^ae^{-i*p*x/\hbar}dx\sqrt{\frac{2}{a}}\text{Sin}\left[\frac{n*\text{Pi}*x}{a}\right][/itex]


Considering that the well has a zero potential between 0 and a.
 
Last edited:
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Right. The momentum-space wave function is simply the Fourier transform.
 
ok thanks !
 

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