Quantum Teleportation and Fusion

menergyam
Messages
21
Reaction score
0
So it seems real obvious to me at the moment that if quantum teleportation becomes common day, then one huge benefit is fusing two hydrogen nuclei by teleporting them at the same location, or very close to each other. Is this a correct assumption, or is this question completely lacking understanding of quantum teleportation?

Actually if my question is a valid one, what would actually happen if you teleport two atoms in the exact same location? Would they explode?
 
Physics news on Phys.org
menergyam said:
Is this a correct assumption, or is this question completely lacking understanding of quantum teleportation?

The latter.

Q. Teleportation means the communication of quantum information, not relocation of matter.

...you may be looking for quantum tunnelling.
 
Last edited:
Can you tunnel one nuclei with another? Would this take just as much energy as normal fusion reactors use today?
 
The matter can not propagate as fast as light.
Information can not propagate faster than light.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
I am reading WHAT IS A QUANTUM FIELD THEORY?" A First Introduction for Mathematicians. The author states (2.4 Finite versus Continuous Models) that the use of continuity causes the infinities in QFT: 'Mathematicians are trained to think of physical space as R3. But our continuous model of physical space as R3 is of course an idealization, both at the scale of the very large and at the scale of the very small. This idealization has proved to be very powerful, but in the case of Quantum...
Thread 'Lesser Green's function'
The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...
Back
Top