Qubit mixed state density matrix coordinates on a Bloch ball

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SUMMARY

The discussion centers on calculating the coordinates of a qubit's mixed state on the Bloch ball using its density matrix representation. The density matrix is expressed as ##\rho=p_{00}|0\rangle \langle 0|+p_{01}|0\rangle \langle 1|+p_{10}|1\rangle \langle 0|+p_{11}|1\rangle \langle 1|##. Participants confirm that diagonalizing the density matrix is necessary to derive the coordinates using the formula ##(\sum p_i x_i, \sum p_i y_i,\sum p_i z_i)##. A practical method for conversion from the qubit density matrix to the Bloch vector is provided, emphasizing that the process involves straightforward arithmetic operations.

PREREQUISITES
  • Understanding of qubit density matrices
  • Familiarity with the Bloch sphere representation
  • Basic knowledge of complex numbers and their operations
  • Experience with linear algebra concepts, particularly matrix diagonalization
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  • Study the process of diagonalizing density matrices in quantum mechanics
  • Learn about the mathematical properties of the Bloch sphere
  • Explore the implications of mixed states in quantum computing
  • Investigate the use of Python for quantum state manipulation, particularly using libraries like Qiskit
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Quantum computing enthusiasts, physicists, and software developers working with quantum algorithms who seek to understand the representation of qubit states on the Bloch sphere.

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What are the coordinates on the 3D Bloch ball of a qubit's mixed state of the form:
##\rho=p_{00}|0\rangle \langle 0|+p_{01}|0\rangle \langle 1|+p_{10}|1\rangle \langle 0|+p_{11}|1\rangle \langle 1|##

451px-Bloch_sphere.svg.png
 
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Do we have to diagonalize the density matrix everytime and then use the formula for the coordinates
##(\sum p_i x_i, \sum p_i y_i,\sum p_i z_i)## ?
https://en.wikipedia.org/wiki/Bloch_sphere

Not very practical.
 
From stackoverflow: "Convert from qubit density matrix to Bloch vector"

Code:
def toBloch(matrix):
   [[a, b], [c, d]] = matrix
   x = complex(c + b).real
   y = complex(c - b).imag
   z = complex(d - a).real
   return x, y, z

In other words, yes you have to use the formula. But I'm not sure why you think it's impractical... it's just three additions/subtractions.
 

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