Engineering Question about a circuit to be solved with Norton's theorem

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When short-circuiting terminals a-b in a circuit, the 5-ohm resistor can be ignored because it is effectively in parallel with a zero-ohm resistor, resulting in zero resistance. This principle is rooted in the fundamentals of circuit analysis, specifically applying Norton's theorem. The discussion highlights a common misunderstanding among newcomers regarding the impact of short circuits on resistors. The user expresses gratitude for the clarification and acknowledges a mix-up in referencing the correct figure. Understanding these concepts is crucial for effective circuit analysis.
link223
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Homework Statement
See picture please, it is highlighted in yellow.
Relevant Equations
Norton's theorem
Hello guys, I am new here.
I was wondering whether I could get some help about the highlighted part. What I don't understand is why we are able to ignore the 5-ohms resistor when we have short circuited terminals a-b.

Thanks in advance.
1650705027062.png
 
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Welcome to PF.
link223 said:
What I don't understand is why we are able to ignore the 5-ohms resistor when we have short circuited terminals a-b.
Because a zero ohm resistor in parallel with a 5 ohm, (or any other resistor) is going to be zero ohms.
 
Baluncore said:
Welcome to PF.

Because a zero ohm resistor in parallel with a 5 ohm, (or any other resistor) is going to be zero ohms.
Thanks! and thanks once again! I didn't think this through then.. makes total sense (also just noticed I was looking at fig(c) not (b) :'D) Thanks though!
 
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