Question about change in entropy of a compound

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The discussion centers on the change in entropy during the electrolysis of water, specifically the origin of the value 48.7 kJ, which represents the energy required to maintain a constant temperature of 298K in the system. This energy is necessary because the endothermic reaction would otherwise lower the system's temperature. The concept of specific entropy is highlighted, noting that hydrogen and oxygen gases have higher entropy than water, which reduces the electrical energy needed for the reaction. The relationship between energy, pressure, volume, temperature, and charge is explained through a potential equation, emphasizing that the electrolysis process is spontaneous when the change in potential is zero. Overall, the discussion clarifies the interplay between environmental energy input and the thermodynamics of the electrolysis reaction.
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Hello, I was just looking at this site: http://hyperphysics.phy-astr.gsu.edu/HBASE/thermo/electrol.html
which has a value TΔS = 48.7 kJ (change in entropy) ... Which i believe comes from the entropy value 69.91 J/K.
Can someone explain where the value 48.7 kJ comes from? I understand it is the environmental energy 'input' but where did the 48.7 kJ come from? Thanks in advance.
 
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The 48.7 kJ is the amount of energy required to maintain a constant temperature in the system. The electrolysis of water is an endothermic reaction that would otherwise decrease the system's temperature.

In other words, less electrical energy is needed because the environment, which remains at 298K, acts as a heat bath to keep the system at 298K too.

There's another way of looking at things: Hydrogen and oxygen, as gases, have a much larger specific entropy than water. The Second Law favors entropy creation, and this benefit is quantified by the term T\Delta S. As a result, less electrical energy is required from us. (At high enough temperatures, many reactions will therefore run on their own; melting and boiling are two common examples.)

In more technical terms, we could write the system potential Z, where

Z=E+PV-TS-\phi Q

\Delta Z=\Delta E+P\Delta V-T\Delta S-\phi \Delta Q

and \phi and Q are voltage and charge, respectively. The electrolysis reaction will be spontaneous if the change in Z is zero*; that is, the energy E needed to drive the reaction that turns H2O into H2 and O2, plus the energy needed to do work on the environment because H2 and O2 take up more space, minus the energy from the environment to keep everything at 298K (this is the 48.7 kJ), minus the electrical work we do transferring charge at a certain voltage, must be zero. This is the schematic drawn in the link you gave. Does this make sense?

*Any process is spontaneous if the change in appropriate potential is zero. The potential is constructed by starting with E and removing the energy terms associated with constant variables. (This is called a Legendre transform.) PV is a special case that is added, not subtracted, because an increase in volume corresponds to negative work done on a system.
 
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