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According to Wikipedia:http://en.wikipedia.org/wiki/Hilbert_space the inner product \langle x | y \rangle is linear in the first argument and anti-linear in the second argument. That is:
\langle \lambda_1 x_1 + \lambda_2 x_2 | y \rangle = \lambda_1 \langle x_1 | y \rangle + \lambda_2 \langle x_2 | y \rangle
\langle x | \lambda_1 y_1 + \lambda_2 y_2 \rangle = \lambda_1^* \langle x | y_1 \rangle + \lambda_2^* \langle x | y_2 \rangle
That's just the opposite of what I always thought. I thought it was, for the usual Hilbert space of non-relativistic quantum mechanics:
\langle \psi | \phi \rangle = \int \psi^*(x) \phi(x) dx
So it's the first argument, \psi that is anti-linear.
Is the quantum mechanics convention the opposite of the usual Hilbert-space convention, or am I confused?
\langle \lambda_1 x_1 + \lambda_2 x_2 | y \rangle = \lambda_1 \langle x_1 | y \rangle + \lambda_2 \langle x_2 | y \rangle
\langle x | \lambda_1 y_1 + \lambda_2 y_2 \rangle = \lambda_1^* \langle x | y_1 \rangle + \lambda_2^* \langle x | y_2 \rangle
That's just the opposite of what I always thought. I thought it was, for the usual Hilbert space of non-relativistic quantum mechanics:
\langle \psi | \phi \rangle = \int \psi^*(x) \phi(x) dx
So it's the first argument, \psi that is anti-linear.
Is the quantum mechanics convention the opposite of the usual Hilbert-space convention, or am I confused?