Question about humidity in milk

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The discussion revolves around a friend's inquiry about a theoretical approach to calculate the amount of water vapor evaporated from hot milk in a bowl over three hours. The bowl has a 1-liter capacity and an outer radius of 160 mm, with the initial milk temperature at 80°C, cooling to 40°C. Suggestions include using weighing measures at intervals, but the focus remains on a theoretical calculation. The conversation touches on the relevance of Raoult's or Henry's Law, questioning whether the equilibrium percentage of water vapor can be determined based on the dew point of the surrounding air. However, it is noted that the scenario is not ideal and does not represent an equilibrium process. The heat dissipated through evaporation is linked to the quantity of water evaporated and the heat of vaporization, with a reference to transport phenomena principles. The discussion emphasizes the complexity of the situation, suggesting that chemical engineers may have more relevant expertise in this area, while also inviting further feedback on the theoretical calculations.
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Hello everybody,

A friend of mine asked me a question regarding one of his milk-processing techniques. He wants to learn if a mathematical formula or a logical approach can be devised.

Okay, the question involves a 1 liter-volume-bowl, whose outer (bigger) radius is 160 mm. He didn't say the inner (lower) radius of the bowl, as I think he considered it not important. He places hot milk at 80°C inside the bowl, and after three hours, he sees that the temperature is lowered to 40°C. He is wondering the amount of water vapor (humidity) evaporated, but in a theoretical basis. I suggested him that he can try simple weighing measures at different intervals, but he insists on seeing a theory-based calculation scheme.

Any suggestions?
 
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Isn't this a Raoult's (or Henry) Law problem. If you know the percentage water vapor in the surroundings (ie : the dew point of the air in the room, at that particular time), then at any temperature, you can find the equilibrium percentage of water in the solution...can you not?

No, it does not seem like this is the best way to approach the problem. On the other hand, I think it's more likely that water will be added to the milk rather than removed from it. The vapor pressure will decrease with lowering the temperature. Why does he think there will be a loss of water ? And does the milk equilibrate (sit for a long time) at 80C before it is put in the vessel ?

The biggest problem here is that the situation is hardly ideal, nor is it an equilibrium process. Anyways, I need to think about this some more.
 
Heat dissipated through evaporation is quantity of water evaporated times heat of vaporization.
 
It's a common homework problem in transport phenomena classes!...unfortunately, I've forgotten too many of the formulas from that class ;) The basic transport principle is: Q = K*(F2-F1)/R, where Q is a flow rate, F2-F1 is a driving force, and R is the resistance to the flow (note this applies to just about anything; mass diffusion, heat flow, even charge--where it's called "Ohm's Law"). K is a proportionality constant that's sometimes needed to harmonize the units. In the case cited, F2-F1 would be the difference in concentration between the atmosphere in the "boundary layer," and at some point beyond, and R would be due to collisions between the molecules of gas. By integrating the expression with respect to time, you get the amount of mass that was transferred in that time...actually, I think there's a much neater formula than the one I gave, but maybe this will help with the general concept.
 
I think chemical engineers rather than chemists (like me) are more involved with these things. But physicochemical approaches can be devised like russ_waters' one. Please go on giving feedback, and he'll be grateful to you.
 
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