Question about intensity and area

  • Thread starter Thread starter qazxsw11111
  • Start date Start date
  • Tags Tags
    Area Intensity
AI Thread Summary
Intensity is defined as Power divided by Area, and in the context of the Sun's energy reaching Earth, only the hemisphere facing the Sun receives this energy at any given moment. The area receiving sunlight is effectively projected as a circle, calculated as πR², rather than the full surface area of the sphere. This can be confusing, as the area is indeed a hemisphere, but from the Sun's perspective, it appears as a circular area. It's important to note that the equation for intensity is accurate only when the area considered is perpendicular to the direction of the incoming radiation. Understanding these distinctions clarifies the relationship between intensity, power, and area in this context.
qazxsw11111
Messages
95
Reaction score
0
Hi everyone. Firstly, I know that intensity= Power/Area. But this question made me my mind confused.


The question shows the sun shining upon the Earth and the soln is:

Only the hemisphere facing the Sun receives energy at any moment.
power received by Earth
= intensity × area of Earth facing the Sun

And it shows the area of the Earth facing the sun is projected to a circle (pi R square, where R is the radius of the circle)! But shouldn't the area be the half the area of a Earth (sphere)?

Anyone can help me? I am really confused. Thanks.
 
Physics news on Phys.org
Yes, the area is a hemisphere but, when viewed from the Sun's perspective, it looks like a circle with the poles at the top and bottom, and the Equator across the middle.
 
Another way to think of it is that, strictly speaking, your equation "intensity= Power/Area" is ONLY correct if the area is perpendicular to the direction of the radiation.
 
Back
Top