Question about kinematic equation

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To solve for final position theta with initial angular velocity at zero, the discussion clarifies that angular acceleration is defined as the change in angular velocity over time. The average angular velocity is derived from the formula w = Δ(theta)/Δt, which leads to confusion about the factor of 2 in the kinematic equation. The correct kinematic equation for angular displacement is theta = (1/2)(ang acc)(t^2), indicating that the factor of 2 accounts for the average angular velocity over the time interval. The displacement theta can also be expressed as the average of the initial and final angular velocities multiplied by time. Understanding these relationships clarifies the derivation of the kinematic equations in rotational motion.
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Assuming initial angular velocity is 0 I want to solve for final position theta

Ang Acceleration = Δw/Δt = w/t

w = Δ(theta)/Δt = theta/t

ang acc = theta/t^2

theta = (ang acc)(t^2)

but how come the kinematic equation is...theta = (ang acc)t^2/2

Where did my 2 go?
 
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Miike012 said:
Assuming initial angular velocity is 0 I want to solve for final position theta

Ang Acceleration = Δw/Δt = w/t

w = Δ(theta)/Δt = theta/t
this formula gives the average angular velocity. You are looking for the instantaneous final angular velocity, which is twice the average.
acc = theta/t^2

theta = (ang acc)(t^2)

but how come the kinematic equation is...theta = (ang acc)t^2/2

Where did my 2 go?
The displacement theta is {(wo+wf)/2} (t)
 
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