Question about light and blackholes

  • Thread starter magus
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Originally posted by magus
i was just wandering..... at the point where gravity is strong enough to be greater than the kinetic energy of which light possesses, do photons of light actually radiate some distance from the collapsed star then slow to rest and fall back to the surface, as a cannonball being shot straight up in Earth's atmosphere would, or at this point are the particles simply not capable of being emitted. or is their some other explanation of which i have not accounted for.
the point of which you are speaking, is called the event horizon. light particals are not able to withstand the graivty of the sigularity. Thus they are sucked in. They don't go out and then get sucked into a black hole, they just go into the black hole. Now when they are sucked in, they give of a nasty gamma burst that is detectible. They give this off because of the energy that is involved with clashing into a singulary which is like smashing into Earths atmosphere. And that is what can detect it, with other obsevations of course.
the event horizon is the edge of a black hole. the gavity there is greater than you can imagine. if light is going into the black hole, you are not going to see it. When light clashes with the event horizon of a black hole, it give off gamma rays. Thats it, that is the only way to see it. If you could optically see a black hole, it wouldn't be a black hole
Re: Re: question about light and blackholes

When light clashes with the event horizon of a black hole, it give off gamma rays.
No, it doesn't. It just falls in. When people say that black holes radiate X-rays and gamma rays and such, that radiation comes from matter which is outside of the black hole.

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