A 23 kg child goes down a straight slide inclined 38 degrees above horizontal. The child is acted on by his weight, the normal force from the slide, and kinetic friction. How large if the normal force of the slide on the child.
The Attempt at a Solution
Kfy + ny + wy=may=0 where Kf stands for kinetic friction, n stands for the normal force, and w stands for the weight.
0 + n-177.6=0
225.4 is the weight. I drew the triangle to find the x and y components of the weight such that the angle being given was = to the value of theta i used. Is 177.4 N for the the normal force correct? I want to make sure my equations are correct also because I just started doing problems where you have to break the weight into x and y components. Thanks.