Question about output voltages and impedances

AI Thread Summary
The discussion focuses on solving two electrical circuit problems involving output voltages and impedances. In the first problem, measurements of output voltage with different load resistances are used to determine the source voltage and resistance, leading to a calculated output voltage of 5.5 volts when Rload equals Rsource. The second problem involves using a voltage divider formula to find an unknown impedance, resulting in a calculated value of approximately 653.714 Ohms for Z2. Participants emphasize the need to create equations based on the given data points to solve for the unknowns effectively. The conversation highlights the importance of understanding relationships between resistances and voltages in circuit analysis.
Mohamed Abdul

Homework Statement


1. For the first measurement, a load resistance Rload = 119Ohms results in an output voltage V(OUT) = 11Volts. For the second measurement, Rload = 11Ohms results in an output voltage V(OUT) = 3.2Volts. From these two measurements, determine the output voltage V(OUT) when Rload = Rsource. You will have to first determine Rsourceand Vsource to answer this question. Express your answer in Volts. Note that the answers will not necessarily be consistent with any source we have seen but should not be unreasonable.

2. A voltage divider is used to determine the input impedance of an unknown circuit. The circuit of figure 1 in the Wikipedia entry on the voltage divider (https://en.wikipedia.org/wiki/Voltage_divider) is used as the model. Assume that Vin = 12Volts, Z1 = 410Ohms, and Vout = 58% of Vin. Determine the value of Z2 if you assume the input impedance is totally resistive.

Homework Equations


Vout = Vin(R2/(R1+R2))

The Attempt at a Solution


For the first problem, I knew that the greater Rload, the closer Vout would be to the actual source voltage. Thus I assumed that Vsource was 11Volts since 119 Ohms >> 11 Ohms. Plugging that in the equation where R1=R2, I got:

Vout = 11(R/2R) -> Vout = 11(1/2) -> Vout = 5.5 Volts.

For the second one, I used the voltage divider formula with the impedences and got:
.65Vin = Vin(Z2/(Z1+Z2)) -> .65Z1 + .65 Z2 = Z2 -> .65Z1 = .35Z2 -> .65(352)/.35 = Z2 = 653.714 Ohms.

Overall I feel like my work was correct but I'm unsure if I used the correct methods. These are a bit different than what we do in class so I'm not too sure.
 
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This is what the circuit looks like for the first problem, by the way. As of now I have managed to figure out the second question but I am still struggling with this one.
 

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You have 2 unknowns (Vsource and Rsource) so you will need to write 2 equations using the two data points (119R, 11V and 11R, 3.2V) and solve them.
 
CWatters said:
You have 2 unknowns (Vsource and Rsource) so you will need to write 2 equations using the two data points (119R, 11V and 11R, 3.2V) and solve them.
Is that the only way to figure out the solution. Isn't there another way to find the output voltage by looking at the relationships between the resistances and voltages?
 
CWatters said:
You have 2 unknowns (Vsource and Rsource) so you will need to write 2 equations using the two data points (119R, 11V and 11R, 3.2V) and solve them.
I checked my answer using your method, and it was correct. Thank you very much for helping me.
 
Yes your method might work because 119 Ohms >> 11 Ohms. That won't always be the case.
 
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