From what I know, to get the reverse trace form of the Einstein field equations, you must multiply both sides by g(adsbygoogle = window.adsbygoogle || []).push({}); ^{ab}(I didn't have a lot of time to make this thread so I did not spend time finding the Greek letters in the latex).

This turns:

R_{ab}- [itex]\frac{1}{2}[/itex]g_{ab}R= kT_{ab}(where k= (8[itex]\pi[/itex]G)/c^{4})

into this:

R- [itex]\frac{1}{2}[/itex]R = kT

which equals:

[itex]\frac{1}{2}[/itex]R = kT

which yields

R= 2kT= LT (I set L= 2k).

However, many sources say that the reverse trace is:

R= -LT

Why is it negative? Is it based on sign signature?

Note that I general, I use (- + + +) signature.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Question about reverse tracing the Einstein field equations

**Physics Forums | Science Articles, Homework Help, Discussion**