- #1

Drao92

- 72

- 0

I have some questions about this detector.

So i have a project about this detector, i made some experiments, made some graphs, answering to some questions, but one questions is struggling me.

How can we avoid to calculate the solid angle, i mean in what situations?

In my lab documents i have this formula: omega`/4*pi=1/2(1-1/(sqrt(1+b^2/4D^2))

where D is the distance from detector and radioactive source, b is the diametre of circular window of the detector.

However, i used a radioactive source with bigger diametre than b so i must mutiple that formula with 8D^2/d^2(1-1/(sqrt(1+d^2/4D^2)) where d is the diametre of the source

So omega/4*pi=omega`*4pi/the above formula^.

So, this is my answer: When the distance is almost 0, 8D^2/d^2(1-1/(sqrt(1+d^2/4D^2)) becomes 0, so the omega angle is 0.

Its my answer good? Are there more answers ?

Sorry for my english, but its not my first language.

Thanks for any help!