Question about Tension 100 identical blocks

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The discussion revolves around calculating the tension in strings connecting identical blocks on a frictionless surface when a force of 100 N is applied to the first block. The tension in the string between block 100 and block 99, as well as between block 50 and block 51, needs to be determined using the equation T2 - T1 = ma. It is clarified that all blocks share the same acceleration, allowing for simplification by treating groups of blocks as single masses. An additional scenario is introduced where a friction coefficient of 0.1 is considered, affecting the calculations of tension by introducing friction forces proportional to the number of blocks. Understanding these principles aids in correctly determining the tensions in the system.
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Each of 100 identical blocks sitting in a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force 100 N.

a) what is the tension in the string connecting block 100 to block 99

B) what is the tension in the string connecting block 50 to 51?

I don't know how to do this. The only equation I got was T2-T1=ma for box 99 where T2 is the tension string attaching to box 98 and T1 is the tension in the string attached to 100. Also for box 100 I got -T=ma and plugged this into the equation -100 + T=ma and got T=50 N but this is wrong for part A and is supposed
To be the answer for part B but I don't see why. Can you please explain how to do this?
 
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Assuming the string doesn't stretch, all the masses will have the same acceleration. So, think of the entire set of blocks as a single mass being pulled and solve for the acceleration. Then you can determine the string tension between any of the blocks by considering all blocks upstream to be a single mass and all blocks downstream to be a single mass, thereby having a two block system.
 
Does this picture make it any easier? All the blocks accelerate the same but you can combine blocks.

blocks.JPG



oops, edit, someone answered whilst I was drawing.
 
So if there were a coefficient of friction of say 0.1 in this problem, then the 99 blocks together would produce a friction force of 0.1 x 99M x g and the one block to the right would produce a friction force of 0.1 x M x g.
And each of these two friction forces would be the amount that is added to its corresponding equation. Right?
 
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