- #1
Amadeo
- 28
- 9
- TL;DR Summary
- Derivation of Equation of Vibration
For undamped free vibrations, we have the following differential equation.
mu'' + ku = 0
where m is the mass of the object hanging on the end of a spring, and u is the distance from the equilibrium position as a function of time.
This yields u = Acosωt + Bsinωt
where ω is √(k/m) (k=spring constant).
I am having trouble understanding why this can be rewritten as
u = RcosΦcosωt + RsinΦsinωt (which, in turn, = Rcos(ωt -Φ) )
If A represents the initial displacement from equilibrium (ui), I can see how we could set this equal to RcosΦ, (R being the maximum displacement) thereby defining Φ to be that value which makes ui=RcosΦ true. But, I don't see why B must, in that case, necessarily be RsinΦ.
It looks like B must be the initial velocity (vi) multiplied by m/k.
mu'' + ku = 0
where m is the mass of the object hanging on the end of a spring, and u is the distance from the equilibrium position as a function of time.
This yields u = Acosωt + Bsinωt
where ω is √(k/m) (k=spring constant).
I am having trouble understanding why this can be rewritten as
u = RcosΦcosωt + RsinΦsinωt (which, in turn, = Rcos(ωt -Φ) )
If A represents the initial displacement from equilibrium (ui), I can see how we could set this equal to RcosΦ, (R being the maximum displacement) thereby defining Φ to be that value which makes ui=RcosΦ true. But, I don't see why B must, in that case, necessarily be RsinΦ.
It looks like B must be the initial velocity (vi) multiplied by m/k.