Question about the Derivation of the Stream-function for a Doublet

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The discussion centers on the derivation of the stream function for a doublet, specifically addressing two main questions. The first question involves the necessity of dividing by the distance between two sources, s, before taking the limit, with the explanation focusing on the need to account for the cancellation of sources. The second question examines why the derivation yields different results when the source and sink positions are swapped, leading to a change in the sign of the stream function. It is clarified that swapping the locations results in fluid velocities moving in opposite directions, which aligns with physical expectations. The conversation emphasizes understanding the mathematical reasoning behind these derivations and their implications in fluid dynamics.
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This is a question about the derivation of the stream-function of a doublet using potential flow theory
Hi,

I just wanted to ask a question about the derivation of the stream function \psi for a doublet. In the pictures below is a derivation (in this one the source is on the left and the sink is on the right). I understand everything in the left photo, however my questions are:

1) Why do we divide by the distance between two sources s before taking the limit? I cannot really understand the reason provided. I understand that the sources will cancel out, but am unclear as to why that means that we need to counter that by including a \frac{1}{s} term.

2) Why does the derivation come out differently if we swap the placements of the source and sink? Intuitively, I feel that I have made an algebraic error, but I fail to see it. If we place the source on the right and the sink on the left, then we will get:
\psi = \frac{m}{2 \pi} \theta_{source} - \frac{m}{2 \pi} \theta_{sink} = \frac{m}{2 \pi} \left( atan(\frac{y}{x-s}) - atan(\frac{y}{x+s}) \right). Now we will get the same expression as before (except we have +m instead of -m), except we will end up with a different sign at the end. Surely, the end result should be the same irrespective of the original geometry.

I would appreciate any help. Thanks in advance.

Screen Shot 2020-01-12 at 12.03.18 PM.png
Screen Shot 2020-01-12 at 12.03.24 PM.png
 
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If you swap the locations, the fluid velocities (calculated from the derivatives of the stream function) are, as expected physically, in the opposite direction. So what's the problem?
 
Chestermiller said:
If you swap the locations, the fluid velocities (calculated from the derivatives of the stream function) are, as expected physically, in the opposite direction. So what's the problem?
Ah yes, that is true. Thank you.

Do you know the reason behind the division by \frac{1}{s}?
 
Master1022 said:
Ah yes, that is true. Thank you.

Do you know the reason behind the division by \frac{1}{s}?
You are determining the limit as the two charges are very close together.
 
Chestermiller said:
You are determining the limit as the two charges are very close together.
I understand the intuition, but why does that mean that we need a \frac{1}{s} term
 
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