Question about the sign of output voltage in clipper circuits

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In clipper circuits, the labeling of terminals as positive or negative depends on the polarity of the input voltage. When the input voltage is positive, the upper terminal is labeled as + and the lower as -; this reverses when the input is negative. The confusion arises from the ability to flip the circuit, which can lead to different interpretations of terminal labeling. For a DC input of +20V, the output will reflect the clipping action of the circuit, while a -20V input will yield a different output based on the circuit configuration. Understanding the circuit orientation and the nature of the input voltage is crucial for accurate labeling and predicting output behavior.
iampaul
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I have attached an image of a clipper circuit below.

First Question: When the sinusoidal input is positive or negative, how do i know how to label it in the
 

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This picture tells all you need to know about AC current

attachment.php?attachmentid=48819&stc=1&d=1341222430.png


Any more questions?
 

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sorry for the post, it isn't complete, i was interrupted by my classmates while typing.
Here's the continuation:
What I'm actually trying to ask is how do i label the positive and negative signs. I can't express myself clearly in English so i'll just give the situation: My professor labels the upper terminal in the input side as + and the lower terminal as - when the input voltage is positive and when the input is negative, the positive and negative signs are reversed. how do i know how to label the terminals when the input is positive or negative. I'm confused because, if i flip over the circuit, doing the opposite is also valid...
 
Just to clarify my question: Vin in the image I've given is positive and my professor has labelled the upper terminal in the input as + and the lower labelled as -. When the input is negative the + sign goes down and the - sign goes up.
Is it not possible that the when Vin is positive, the upper terminal is - and the lower is +.
If i flip the circuit backwards, this is the result.
 
Assume that the input is DC instead of AC.
If the input is +20V what is the output?
If the input is -20V what is the output?
 
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