Question Concerning F=ma and FBDs.

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In analyzing forces using free body diagrams (FBDs), the order of forces in the equation \(\sum F = ma\) depends on the chosen positive direction. For a block supported by a string, the forces can be expressed as either \(T - mg = ma\) (if upward is positive) or \(mg - T = ma\) (if downward is positive). The choice of direction affects the sign of acceleration but not its magnitude. When dealing with multiple masses, it's important to maintain consistency in how forces are represented, either by aligning them in the same order or ensuring the larger force is listed first. Ultimately, the key is to clearly define the positive direction to avoid confusion in calculations.
lawtonfogle
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Ok, I know that, using a FBD, one is susposed to use \sum F = m a
My question is what order do you put the forces that \sum F equal
An example might help me explain my question.
Lets take a block of wood that is supported by a string. The only forces acting on it are mg and T
So...
\sum F = ma
T - mg = ma
or
mg - T = ma.
I know if a = 0 it does not matter, but how does one decide what order to put th forces in when there is acleration?
 
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The \sigma should be a capital sigma.I fixed it.
 
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It depends on how you choose the positive and negative directions.
T - mg = ma1, you've chosen the positive direction upwards.
mg - T = ma2, you've chosen the positive direction downwards.

T - mg = ma1 = -(mg - T) = -ma2

In the case that mg is greater than T, the acceleration's negative when you've chosed the positive direction upwards, and positive when you've chosen the positive direction downwards. The magnitude does not change.
 
So on an Atwood machine, I should chose it so that both masses are the same way written (both T - mg, or vice versa), or so that the greater force is first.
 
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