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Question from simple lens diagram (camera)

  1. 1. The problem statement, all variables and given/known data
    A simple camera has a converging lens of focal length 50.0 mm.

    It is used to photograph a tree 3.00 m high.

    The tree is 8.00 m away from the lens.

    Calculate the distance v between the lens and the film, giving your answer in mm to three significant figures.


    2. Relevant equations

    1/f = 1/u + 1/v

    3. The attempt at a solution

    1/50 = 1/8000 + 1/(-v)
    v = -50.3 mm

    Is this correct? Thank you! :smile:
     
  2. jcsd
  3. Why did you reason that the image distance was negative?
     
  4. Hmmm, not sure why I done that actually...

    Have corrected to:

    1/f = 1/u + 1/v

    1/50 = 1/8000 + 1/v

    v = 50.3 mm
     
  5. That looks right. The negative image distance you got before implies that the film needed to be outside the camera to capture the image.
     
  6. Thanks Squeezebox!

    When I want to calculate the linear magnification of the image, the following equation is used:

    m = v/u

    Do I use the same v and u values from above? (both in metres)

    i.e.

    0.0503 / 8 = 0.0063
     
  7. Now you have the opposite problem. There's a negative sign in this one.

    m= -v/u

    The image gets flipped upside down. This happens with your eyes too; your brain flips the image back right side up.
     
  8. Ah, so it'd be

    -0.0503 / 8 = -0.0063

    So is the height of the tree, stated in the question as being 3.00 m, not required to obtain the linear magnification?
     
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