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CHECK OUT THIS PROBLEM
A SQUARE PLATE OF SIDE 5 cm IS ROTATING AROUND ONE OF ITS EDGES. IF THE ANGULAR ACCELARATION OF THE BODY IS 0.2 rad/s/s, FIND THE TORQUE.
ANSWER:2.0 * 10^(-5)
(TWO INTO 10 RAISED TO -5)
A SQUARE PLATE OF SIDE 5 cm IS ROTATING AROUND ONE OF ITS EDGES. IF THE ANGULAR ACCELARATION OF THE BODY IS 0.2 rad/s/s, FIND THE TORQUE.
ANSWER:2.0 * 10^(-5)
(TWO INTO 10 RAISED TO -5)