What is the area of a receiving antennae with an angular spread of θ = λ/d?

  • Thread starter Thread starter Biosyn
  • Start date Start date
  • Tags Tags
    Angular
AI Thread Summary
The discussion revolves around calculating the area of a receiving antenna with an angular spread defined by θ = λ/d, where λ is the wavelength and d is the distance. The provided values are λ = 5*10^-2 m and d = 3*10^3 m, leading to an angular spread calculation. The spatial spread is determined by multiplying the angular spread by the distance the beam travels, resulting in an approximate area of 1 km². However, a more precise calculation suggests the area is closer to 0.54 km², indicating potential errors in the initial assumptions or calculations. The conversation emphasizes the importance of accuracy in deriving the area from the angular spread.
Biosyn
Messages
114
Reaction score
0

Homework Statement



I just have a question on finding the area of a receiving antennae. The answer says the area is about 1km. I got an answer close to 1 km.

λ = 5*10-2 m
d = 3*103 m

The angular spread is θ = λ/d

θ= \frac{5*10<sup>-2</sup>}{3*10<sup>3</sup>}

The spatial spread is the diameter of the beam on the target. So that means it is the angular spread times the distance the beam travels. Correct?

S = r*θ
S = (5*10^7 m ) * θ
S ≈ 1 km The area of the receiving antennae is them [1km / 2 ]2 * ∏ = 0.78km which is about 1 km.
 
Physics news on Phys.org
The S ≈ 1 km approximation is rather rough. 830m is closer, and that leads to a final answer of about .54 km2 (note: km2, not km). This suggests you have an error somewhere else, but I'm not qualified to say where.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top