Question on General Relativity

eoghan
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Hi!
I'm reading General Relativity by Wald. In chpater 4.4a about Newtonian limit of linearized gravity, it says:
"When gravity is weak, the linear approximation to GR should be valid. The assumptions about the sources (relative motion << c and material stresses << mass-energy density) then can be formulated more precisely as follows: there exists a global inertial coordinate system of \eta_{ab} such that:
<br /> T_{ab} \approx \rho t_a t_b<br />
where t_a=(\frac{\partial}{\partial x^0})_a is the "time direction" of this coordinate system."

I've always thought that
<br /> T_{ab} \approx \rho v_a v_b<br />
where v is the velocity of the observer (or in other words, the relative velocity between the source and the observer). So, how can I say that
<br /> v_a=(\frac{\partial}{\partial x^0})_a<br />
?
 
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That means that the components v^{\mu} of the velocity vector are given by

<br /> v^{\mu} = \frac{dx^{\mu}}{d\tau} \approx (1,0,0,0)<br />

This is the same as saying

<br /> \frac{dx^0}{d\tau} &gt; &gt; \frac{dx^i}{d\tau}<br />

which is the non-relativistic limit.
 
Thank you!
 
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