Something got left out in your cut and paste. Did you mean that a(t) = 1.23t ?njt84572 said:The acceleration of a bus is given by a(t)=at where = 1.23 is a constant.
That defines average acceleration. Not useful here. (Unless I have guessed wrong about your problem.)a=v2-v1/t2-t1
Velocity at T1 and T2 refers to the speed and direction of an object at two specific points in time, T1 and T2. It is a measure of how quickly an object's position changes over a certain period of time.
Velocity at T1 and T2 can be calculated by dividing the change in position (displacement) by the change in time between T1 and T2. This can be represented by the equation v = (x2 - x1) / (t2 - t1), where v is velocity, x is position, and t is time.
Velocity at T1 and T2 is the instantaneous velocity at two specific points in time, while average velocity is the overall velocity over a certain period of time. Average velocity is calculated by dividing the total displacement by the total time.
Acceleration is the rate of change of velocity, so it can affect the velocity at T1 and T2 by either increasing or decreasing it. If an object is accelerating, its velocity at T1 and T2 will be different from its average velocity.
Yes, velocity at T1 and T2 can be negative if the object is moving in the opposite direction of the chosen positive direction. It can also be negative if the object is slowing down or decelerating.