Question on waves where a rope attached to ceiling.

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A uniform rope of mass m and length L hangs from a ceiling, with a segment of mass M below point P. The tension in the rope is derived from Newton's second law, leading to the conclusion that the speed of a transverse wave is a function of the distance y from the lower end, expressed as v = √(gy). For part (b), the time T for a wave to travel the length of the rope is determined to be T = 2√(L/g). The discussion includes confusion about the relationship between speed and time, indicating a need for clarification on wave dynamics. Understanding these principles is essential for solving the problem accurately.
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Homework Statement


A uniform rope of mass m and length L hangs from a ceiling. The mass of the rope below a point P is M.

(a) Write down Newtons second law for the segment of the rope of mass M and find the tension ata distance y above the lower end of the rope. Show that the speed of a transverse wave on the rope is a function of y, the distance from the lower end, and is given by v = sqr(gy).

(b) Show that the time a transverse wave takes to travel the length of the rope is given by T = 2sqr(L/g)

***

(a) v = sqr(tension/[mu]), where tension= Mg, and [mu] = M/y --- I think that's right.



b) i do not have a clue for this bit am i meant to use speed= distance over time. If so the speed can't be the speed calculated in a) as then i do not get that answer.
Thanks.



The Attempt at a Solution

 
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You have v = √(g/y). If x=x(t) is the distance of a wave crest from the bottom of the rope at time t, what differential equation can you write down for x?
 
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