- #1
mathyou9
- 8
- 0
For both time dilation equations (kinematic and gravitational) I have often seen
[tex]\Delta t^\prime = \frac{\Delta t}{\sqrt{1-(v/c)^2}}[/tex]
and
[tex]\Delta t' = \frac{\Delta t}{\sqrt{1-\frac{2GM}{rc^2}}}[/tex]
I'll calls these equations as "Set A"
------------------------
And at other times as
[tex]\Delta t = \frac{\Delta t_0}{\sqrt{1-(v/c)^2}}[/tex]
and
[tex]\Delta t = \frac{\Delta t_0}{\sqrt{1-\frac{2GM}{rc^2}}}[/tex]
I'll calls these equations as "Set B"
---
I'm no physics (or mathematics) major (just a dilettante; that's why I'm asking.) Why use t' (on the left side of the equals sign for "Set A" equations) but t0 (on the right side of the equals sign for "Set B" equations)? I realize an equation is only good as far as you can interpret it. And so I know these are the same equations, but why the difference?
Thanks. :)
[tex]\Delta t^\prime = \frac{\Delta t}{\sqrt{1-(v/c)^2}}[/tex]
and
[tex]\Delta t' = \frac{\Delta t}{\sqrt{1-\frac{2GM}{rc^2}}}[/tex]
I'll calls these equations as "Set A"
------------------------
And at other times as
[tex]\Delta t = \frac{\Delta t_0}{\sqrt{1-(v/c)^2}}[/tex]
and
[tex]\Delta t = \frac{\Delta t_0}{\sqrt{1-\frac{2GM}{rc^2}}}[/tex]
I'll calls these equations as "Set B"
---
I'm no physics (or mathematics) major (just a dilettante; that's why I'm asking.) Why use t' (on the left side of the equals sign for "Set A" equations) but t0 (on the right side of the equals sign for "Set B" equations)? I realize an equation is only good as far as you can interpret it. And so I know these are the same equations, but why the difference?
Thanks. :)