I have the next decay:(adsbygoogle = window.adsbygoogle || []).push({});

[tex]B^0 \rightarrow D^+ e^- \nu_e[/tex]

The question is:

employ CP symmetry on the particles in this proccess, what reaction would you get?

and what would happen if CP symmetry breaks?

Now if I employ CP symmetry I get:

[tex]B^0 \rightarrow D^- e^+ \bar{\nu_e}[/tex]

But in my notebook it's written that weak interaction violates CP symmetry, and this proccess is obviously weak.

Now that I read Wikipedia's entry I read the CP violation was found in Kaons and that it's small, so I guess CP doesn't get violated here, only C symmetry and P symmetry.

Now if CP symmetry gets violated what will I see is that the last proccess will never get detected in experiments cause CP get violated in the first proccess.

Is my reasoning correct or flawed?

Thanks in advance.

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# Question regarding CP symmetry and weak interaction

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