Question regarding CP symmetry and weak interaction

[MathematicalPhysicist]

I have the next decay:

$$B^0 \rightarrow D^+ e^- \nu_e$$

The question is:
employ CP symmetry on the particles in this process, what reaction would you get?
and what would happen if CP symmetry breaks?


Now if I employ CP symmetry I get:
$$B^0 \rightarrow D^- e^+ \bar{\nu_e}$$

But in my notebook it's written that weak interaction violates CP symmetry, and this process is obviously weak.

Now that I read Wikipedia's entry I read the CP violation was found in Kaons and that it's small, so I guess CP doesn't get violated here, only C symmetry and P symmetry.

Now if CP symmetry gets violated what will I see is that the last process will never get detected in experiments cause CP get violated in the first process.

Is my reasoning correct or flawed?

Thanks in advance.

 

[mathman]

I am not acquainted with the particular process, but in general CP violation is observed by seeing a quantitative difference in processes which should have the same probability.