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Question regarding CP symmetry and weak interaction

  1. Jun 28, 2010 #1


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    Gold Member

    I have the next decay:

    [tex]B^0 \rightarrow D^+ e^- \nu_e[/tex]

    The question is:
    employ CP symmetry on the particles in this proccess, what reaction would you get?
    and what would happen if CP symmetry breaks?

    Now if I employ CP symmetry I get:
    [tex]B^0 \rightarrow D^- e^+ \bar{\nu_e}[/tex]

    But in my notebook it's written that weak interaction violates CP symmetry, and this proccess is obviously weak.

    Now that I read Wikipedia's entry I read the CP violation was found in Kaons and that it's small, so I guess CP doesn't get violated here, only C symmetry and P symmetry.

    Now if CP symmetry gets violated what will I see is that the last proccess will never get detected in experiments cause CP get violated in the first proccess.

    Is my reasoning correct or flawed?

    Thanks in advance.
  2. jcsd
  3. Jun 28, 2010 #2


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    Science Advisor

    I am not acquainted with the particular process, but in general CP violation is observed by seeing a quantitative difference in processes which should have the same probability.
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