*Quick Linear equation - Equation of a line - Thanks

AI Thread Summary
To find the equation of a line through the points (-3, 5) and (1, -3), the initial equation derived is y - 5 = -2(x + 3). This simplifies to y - 5 = -2x - 6, leading to y = -2x - 1 after isolating y. The confusion arose from incorrectly simplifying the initial equation, particularly with handling the double negative. The final equation, y = -2x - 1, is confirmed by correctly applying distribution and addition. Understanding these steps clarifies the process of deriving the line's equation.
nukeman
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Homework Statement



Determine an equation of a line through -3,5 and 1, -3

so... What i got is

y - 5 = -2(x-(-3) )

So that turns into

y - 5 = -2x + 3 correct?

now i am suppose to simplify, and the answer is

y = -2x -1

how did they get y = -2x -1 from y - 5 =-2x + 3

?? Can anyone please explain the steps they did to get that final answer?


Homework Equations





The Attempt at a Solution

 
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y - 5 = -2(x-(-3) ) Does NOT turn into y - 5 = -2x + 3?

Deal with the double negative first, then distribute the -2 to ALL terms it’s multiplied by, so:

y - 5 = -2(x-(-3) ) -> y - 5 = -2(x+3) -> y - 5 = -2x-6 -> y= -2x-1
 
wow, thanks. That makes much more sense!

ok so y - 5 = -2x-6

now you to get rid of the y - 5, you ad 5 to both sides correct?


y= -2x-1


JonF said:
y - 5 = -2(x-(-3) ) Does NOT turn into y - 5 = -2x + 3?

Deal with the double negative first, then distribute the -2 to ALL terms it’s multiplied by, so:

y - 5 = -2(x-(-3) ) -> y - 5 = -2(x+3) -> y - 5 = -2x-6 -> y= -2x-1
 
nukeman said:
wow, thanks. That makes much more sense!

ok so y - 5 = -2x-6

now you to get rid of the y - 5, you ad 5 to both sides correct?
You're not getting rid of y - 5 - you're just isolating y to get it all by itself. Yes, you add 5 to both sides.
nukeman said:
y= -2x-1
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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