Quick question about pressure in gases.

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When two gases at different pressures are allowed to mix after removing a partition, the final pressure is not simply the average of the initial pressures. Instead, it depends on both the initial pressures and the volumes of the gases, as described by Boyle's Law: P_f = (P1V1 + P2V2) / (V1 + V2). The complexity increases when calculating entropy change during mixing, as the resulting equation involves P_f and leads to difficulties in simplification. The discussion highlights the need to consider both pressure and volume for accurate calculations in gas behavior. The challenge lies in deriving a clear expression for entropy change in terms of the initial pressures.
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Two gases are in a vessel and separated by a partition. They start at different pressures P1 and P2. When the partition is removed and equilibrium restored am I right in thinking the new pressure is the average of the starting pressure i.e.

P_{f} = \frac{P1+P2}{2}

Thanks.
 
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Nope. Volume and temperature count, too.

What would happen if one side of the vessel contained a thimble full of gas at 100 Pa, and the other side contained a tanker car full at 50 Pa? Would an average make sense?
 
Okay using Boyle's Law I get:

P_{f}=\frac{P1V1+P2V2}{(V1+V2)}

If this is correct, I have the slight problem that my work for the full question (calculate the entropy change when the gases mix) end with:

\Delta S = nR \ln\left(\frac{P1P2}{P_{f}^{2}}\right)

Substituting the first expression in gives a mess, which I can't seem to simplify to give an expression in terms of P1 and P2. Anyone poke me in the right direction?
 
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