Quick question about simplifying a differential equation?

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SUMMARY

The discussion focuses on the simplification of the differential equation \(\frac{2e^{t}+C}{e^{t}} = 2e^{-t} + C\). The user expresses confusion regarding the transformation to \(e^{-t}\) and questions the steps leading to the final result. The correct simplification involves recognizing that \(\frac{e^{t}}{e^{t}} = 1\) and applying the property of exponents, leading to the conclusion that \(C e^{-t}\) is the appropriate form. The user mistakenly equates \(e^{-t}\) to \(-1\), which is incorrect.

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MathWarrior
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I have solved this equation but I am just not quite sure why this final result is the way it is.

\frac{2e^{t}+C}{e^{t}} = 2e^{-t} + C

Why is it e^{-t} when its simplified ?
 
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uhhh, how did you get that?

shouldn't it be...
\frac{2e^{t}+C}{e^{t}}
= 2 \frac{ e^{t} }{ e^{t} } + \frac{ C }{ e^{t} }
= 2 + C e^{-t}
 
I also got e^(-t) = -1
 

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