Quick Question Regarding Smooth Inclined Plan

AI Thread Summary
The discussion focuses on calculating the acceleration of a 6kg block sliding down a 45° inclined plane. The key point is that only the component of the weight parallel to the incline, represented as mg sin(θ), contributes to the block's acceleration. The perpendicular component, mg cos(θ), is balanced by the normal force and does not affect acceleration. The initial confusion about including both components is clarified, emphasizing that only the parallel component is relevant for this calculation. Understanding these forces is crucial for accurately determining the block's acceleration.
FaraDazed
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Homework Statement


an block of mass 6kg is sliding down an inclined plane inclined at 45° to the horizontal. Find the acceleration of the mass.


Homework Equations


F=ma


The Attempt at a Solution


Is it correct that the weight times sin45 will equal ma, because that's how i first did it but now I am going through the problem again before handing it in and drew the sketch again and I was thinking what about the weight times cos45? wouldn't that AND wsin45 cause acceleration?
 
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Only the component of the weight parallel to the incline (mg sinθ) acts to accelerate the block. Perpendicular to the incline, the normal force acts to cancel the component of the weight (mg cosθ).
 
Doc Al said:
Only the component of the weight parallel to the incline (mg sinθ) acts to accelerate the block. Perpendicular to the incline, the normal force acts to cancel the component of the weight (mg cosθ).

Thanks :)
 
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