Quick question regarding speed & constant acceleration

AI Thread Summary
The discussion centers on solving a physics problem involving an antelope's motion with constant acceleration. The key points include determining the antelope's speed at the first point, which is calculated to be 5.74 m/s, and finding its acceleration using kinematic equations. The relevant equations involve distance, time, and final speed, with the assumption that the initial position is zero. The problem-solving approach emphasizes the use of kinematic equations to relate these variables effectively. Understanding these concepts is crucial for tackling similar physics problems.
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I'm doing homework from the first week of Physics 111 in the 2nd chapter (this is university calc-based physics by the way). I am a bit of a slow learner (dyslexic :frown: ), so take it easy on me. I know the answer to the first question, but I would like to understand it. Here is the problem:

An antelope moving with constant acceleration covers the distance 75.0 m between two points in time 7.60 s. Its speed as it passes the second point is 14.0 m/s.

Q1): What is its speed at the first point?
A1): 5.74 m/s

Q2): What is the acceleration?

Thanks guys
 
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Ok so for this type of problem you have to use your kinematic equations. We are given a distance between two points, the time it takes for the antelope to cover that distance, and the speed when it passes the second point. So we need to use an equation that contains all these variables. We would use x = x_{0} + \frac{1}{2}(v_{x}_{0}+v_{x})t. We could rewrite this as x - x_{0} = \frac{1}{2}(v_{x}_{0}+v_{x})t. x - x_{0} is really the distance, so 75 = \frac{1}{2}(v_{x}_{0} + 14)(7.60). So just solve for v_{x}. For the second question, use the equation x - x_{0} = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2}. x_{0} = 0 and you know v_{x}_{0} and t from the previous question. So just solve for a.
 
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courtrigrad said:
Ok so for this type of problem you have to use your kinematic equations. We are given a distance between two points, the time it takes for the antelope to cover that distance, and the speed when it passes the second point. So we need to use an equation that contains all these variables. We would use x = x_{0} + \frac{1}{2}(v_{x}_{0}+v_{x})t. We could rewrite this as x - x_{0} = \frac{1}{2}(v_{x}_{0}+v_{x})t. x - x_{0} is really the distance, so 75 = \frac{1}{2}(v_{x}_{0} + 14)(7.60). So just solve for v_{x}. For the second question, use the equation x - x_{0} = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2}. x_{0} = 0 and you know v_{x}_{0} and t from the previous question. So just solve for a.

do i just assume that X0 (subscript 0) is equal to 0? Like I assume the starting position is 0 in other words
 
yes you assume starting position is 0.
 
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