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The discussion centers on calculating the shortest return trip time for a ferry crossing a river with a tidal current. The initial attempt incorrectly combines the speeds of the ferry and the current as if they were parallel. It is clarified that the ferry's velocity is perpendicular to the riverbank, necessitating a component of the ferry's speed to counteract the current. The correct approach involves considering the ferry's velocity relative to the current to ensure it travels straight across. This highlights the importance of vector components in solving the problem accurately.
jollyrancher9
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A ferry cross a river of width d. The speed of the boat is v relative to the water, and the speed of the tidal current is w parallel to the riverbanks. The ferry landing points are directly opposite each other on each side of the river. How long does the shortest return trip take?

My attempt: vector v and vector w add to form vector v+w, which is directionally a straight line between the 2 ferry landing points. Then, (v+w) = d/t, and t = d/(v+w), where d, v and w are all vectors. Is this correct? The answer seems too simplistic.

Thanks to everyone for taking the time to look at this. Your help is much appreciated!


jollyrancher99
 
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Hello!
v and w are not parallel. Ferry crosses river - its velocity is perpendicular to the riverbank and river flows parallel to the riverbanks. So you can't write t = d/(v+w). For ferry to travel perpendicularly to the riverbank, component of v along riverbank must cancel velocity of the tidal current w. Guess this helps.
 
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