- #1

- 164

- 0

my answer is zero because 26kg times 9.8 m/s^2 = 255 N, so a 104N force wouldnt be enough to move it. does that sound right?

~Amy

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter physicsgal
- Start date

- #1

- 164

- 0

my answer is zero because 26kg times 9.8 m/s^2 = 255 N, so a 104N force wouldnt be enough to move it. does that sound right?

~Amy

- #2

radou

Homework Helper

- 3,120

- 7

physicsgal said:

my answer is zero because 26kg times 9.8 m/s^2 = 255 N, so a 104N force wouldnt be enough to move it. does that sound right?

~Amy

Since there is no friction mentioned, the force should move the mass. It is not the same as lifting the mass. In order to lift it, you should have a vertical force which is greater than the weight of the mass. So, the force F = 104 * cos32 is doing work along a distance of 5 m. Unless I'm missing something big here.

- #3

- 164

- 0

i dunno. it just seems like the 26 kg should be included somehow.

can anyone else shed some insight?

~Amy

- #4

radou

Homework Helper

- 3,120

- 7

physicsgal said:

i dunno. it just seems like the 26 kg should be included somehow.

can anyone else shed some insight?

~Amy

Maybe they're included to confuse you.

- #5

- 164

- 0

k, looks like youre right. thanks for the help!

~Amy

~Amy

- #6

- 164

- 0

part a starts at 40N, 0 displacement in m

then it goes to 40N at 4 m

=160J

then from 40N it slopes at 60N by 8 m

= 200J

so the total = 360J

and the question asks "state two possible outcomes of the work (above) being done on the object". im not sure what "possible outcomes" mean.

~Amy

- #7

radou

Homework Helper

- 3,120

- 7

Could you make a sketch of the diagram and post it on a link?

- #8

- 164

- 0

i dunno how links work. but i'll try to sketch it here just using typing.

N

60......................**/**

....................**/ **

40**------- /**

20

0......2.....4.... 6....8 (displacement in m)

imagine the /s are a straight normal slope..

k, this is the best drawing i can do.

~Amy

N

60......................

....................

40

20

0......2.....4.... 6....8 (displacement in m)

imagine the /s are a straight normal slope..

k, this is the best drawing i can do.

~Amy

Last edited:

- #9

radou

Homework Helper

- 3,120

- 7

- #10

- 164

- 0

thanks anyways.

if anyone else can help, it'd be appreciated!

~Amy

if anyone else can help, it'd be appreciated!

~Amy

- #11

- 1

- 0

Share: