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Race car G problem

  1. Sep 26, 2004 #1
    A particular race car can cover a quarter-mile track (402 m) in 6.27 seconds, starting from a standstill. Assuming the acceleration is constant, how many "g's" does the driver experience?

    This has to be a really easy problem as I am given the m and the sec but I can not figure out what formula to use for this problem...

    Please help.
  2. jcsd
  3. Sep 26, 2004 #2
    x = x + vt + 1/2at^2
    402m = 0 + 0 + 1/2(a)(6.27^2)
    804m = 39.3129a
    a = 804/39.3129
    a = 20.45m/s/s

    since one 'g' = 9.8
    the driver experiences a little bit over 2 g's?
  4. Sep 26, 2004 #3
    OH that makes sense. I was trying to use the formula F=ma to solve the problem. Oops. Thank you much for your assistance.
  5. Sep 26, 2004 #4
    Maybe you could help me with this problem also?
    The position of a mass m = 24 kg is given (in m) by x(t) = 7sin(5t). Calculate the magnitude of the maximum force acting on the mass.

    I know that acceleration is the double prime of the formula but I don't know how to find the maximum force.
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