Radial Acceleration of Point on Planet: Calculate Using v^2/r

portillj72
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Consider a planet of radius 5.53X10^6 m with a rotation period of 24.3 hours. Compute the radial acceleration of a point on the surface of the planet at the equator due to its rotation about its axis.

What is the Radial Acceleration.

I found out that the formula for radial acceleration is v^2/r but I don't know how to make the problem fit into it!
 
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How do you find v? How far does a point on the equator travel in 24.3 hours? v=distance/time.
 
i don't get the distance. the only distance i get is the radius.
 
A point on the equator rotates around the planet once in 24.3 hours. What's the circumference of the planet? It is related to r.
 
ooo so then v = 2pi(r)/t
and then I can plug it in the original formula for the radial acceleration right?
 
thank you so much I got it!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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